yocto-bsp: allow branch display filtering

Add a "branches_base" property that can be used to allow only matching
branches to be returned from all_branches().

(From meta-yocto rev: c3481e22fc4690ff5e449f9c16c2453fa964205d)

Signed-off-by: Tom Zanussi <tom.zanussi@intel.com>
Signed-off-by: Saul Wold <sgw@linux.intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>

scripts/lib/bsp/engine.py

@@ -463,6 +463,11 @@ def gen_choices_defer(input_line, context, checklist = False):
     except KeyError:
         nameappend = ""
 
+    try:
+        branches_base = input_line.props["branches_base"]
+    except KeyError:
+        branches_base = ""
+
     filename = input_line.props["filename"]
 
     closetag_start = filename.find(CLOSE_TAG)
@@ -478,6 +483,8 @@ def gen_choices_defer(input_line, context, checklist = False):
     captured_context["filename"] = filename
     context["nameappend"] = nameappend
     captured_context["nameappend"] = nameappend
+    context["branches_base"] = branches_base
+    captured_context["branches_base"] = branches_base
 
     deferred_choice = (input_line, captured_context, checklist)
     key = name + "_" + filename + "_" + nameappend

scripts/lib/bsp/kernel.py

@@ -713,6 +713,17 @@ def all_branches(context):
 
     branches = []
 
+    base_prefixes = None
+
+    try:
+        branches_base = context["branches_base"]
+        if branches_base:
+            base_prefixes = branches_base.split(":")
+    except KeyError:
+        pass
+
+    arch = context["arch"]
+
     if tmp:
         tmpline = tmp.split("\n")
         for line in tmpline:
@@ -720,6 +731,14 @@ def all_branches(context):
                 break;
             idx = line.find("refs/heads/")
             kbranch = line[idx + len("refs/heads/"):]
+            kbranch_prefix = kbranch.rsplit("/", 1)[0]
+
+            if base_prefixes:
+                for base_prefix in base_prefixes:
+                    if kbranch_prefix == base_prefix:
+                        branches.append(kbranch)
+                continue
+
             if (kbranch.find("/") != -1 and
                 (kbranch.find("standard") != -1 or kbranch.find("base") != -1) or
                 kbranch == "base"):