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rename stuff to write out 'config' instead of 'config.common'. This is my 

first ever attempt to python hackery.  fear.

svn path=/trunk/kernel/source/linux-2.6-2.6.12/; revision=3520
This commit is contained in:
Andres Salomon 2005-07-16 02:18:25 +00:00
parent e70192de4e
commit 593e429b6e
1 changed files with 7 additions and 7 deletions
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14
debian/bin/split.py vendored
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@ -1,11 +1,11 @@
#!/usr/bin/python
#
# Scans underlying directory structure for files with names config.ext
# where .ext is not .stub, .common or .default, and extracts a common
# Scans underlying directory structure for files with names config.*
# where .* is not .stub or .default, and extracts a common
# set of config options from them. The resulting set of options is
# written into the config.common file. On the second pass each config.ext
# written into the 'config' file. On the second pass each config.*
# file is parsed to remove the common config options found in
# config.common, with the results written to config.ext.stub.
# config, with the results written to config.*.stub.
#
import os, string, sys
@ -44,7 +44,7 @@ def walk_callback(arg, dir, names):
if names.count('.svn'): names.remove('.svn')
for name in names:
base, ext = os.path.splitext(name)
if(base == 'config' and ext not in ('.default', '.stub', '.common')):
if(base == 'config' and ext not in ('.default', '.stub', '')):
fname = os.path.join(dir,name)
conffiles.append(fname)
print 'Processing ' + fname + ' ... ',
@ -55,8 +55,8 @@ def walk_callback(arg, dir, names):
# Main routine
#
os.path.walk('.', walk_callback, None)
print 'Writing the config.common output file ... ',
write_out(common, 'config.common')
print 'Writing the config output file ... ',
write_out(common, 'config')
print 'done.'
for fname in conffiles:
print 'Writing the ' + fname + '.stub output file ... ',